Kinematics
In almost every sport, speed is an essential factor in the game. In badminton, the speed or velocity of a player can be modeled by the equation v=d/t, where 'v' is the velocity, 'd' is the distance, and 't' is the time. For example, a shuttlecock travels 5.00 m (N) in 0.800 seconds. Find the velocity. v=5.00/0.800, therefore the velocity of the shuttlecock is 6.25 m/s (N). In 2005, Fu Haifeng of China recorded the fastest badminton smash with a speed of 332 km/h (92.1 m/s). Since in the game of badminton or any other sports, the velocity of an object is not always constant. In result, there will be an acceleration or deceleration. Suppose you are prepared to serve the shuttlecock. Once you hit it, it travels 4.0 m with a velocity of 12 m/s (E). What is the acceleration of the shuttlecock? This question can be calculated by using one of the five equations of linear kinematics.
Equations of linear kinematicsV2=V1+aΔt
Δd=1/2(V2+V1)Δt Δd=V1Δt+(1/2)aΔt^2 Δd=V2Δt-(1/2)aΔt^2 V2^2=V1^2+2aΔd | Δd= 4.0 m V1= 0 V2= 12 m/s (E) a= ? Option 5 includes all the variables needed. | V2^2=V1^2+2aΔd 12^2 = 0 ^2 + 2(a)(4) 144= 0 + 8a a= 18 m/s^2 (E) ∴ the acceleration of the shuttlecock is 18 m/s^2 (E) |
Due to the Earth's gravity, anything that goes up must come down. For example, if an object is thrown in space, it will travel in a straight line until it encounters another object or gravitational field. However, when this same object is thrown on Earth, it creates a parabolic motion instead of a continuous straight line. This parabolic motion is called projectile motion. In badminton, the shuttlecock creates a projectile. Assume that a shuttlecock is hit with a horizontal velocity of 10.
m/s and a vertical velocity of 5.0 m/s. If the shuttlecock was hit from a
height of 2.0 m, how far did it travel? To start this question, you must layout
what is given in horizontal and vertical components.